n^2-n-12/4-n^2(x)n-2/n-4

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Solution for n^2-n-12/4-n^2(x)n-2/n-4 equation: 


x in (-oo:+oo)

n^2-n-(n*n^2*x)-(2/n)-(12/4)-4 = 0

n^2-n-(n^3*x)-2*n^-1-4-3 = 0

n^2-n^3*x-n-2*n^-1-7 = 0 // - n^2-n-2*n^-1-7

-n^3*x = -(n^2-n-2*n^-1-7) // : -n^3

x = (-(n^2-n-2*n^-1-7))/(-n^3)

x = (n-n^2-(-2*n^-1)+7)/(-n^3)

x = (n-n^2-(-2*n^-1)+7)/(-n^3)

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